In an ap the sum of first n terms is 5n 2/2

Author: zcic

August undefined, 2024

WebSo, the sum of the first n terms of an AP is given by S = n/2 [2a + (n 1) d] We can also write as S = n/2 [a + a + (n 1) d] S = n/2 [a + an] (iii) If there are only n terms in an AP, then a n = l, the last term. From (iii), S = n/2 [a + l] (iv) WebSolution Given that sum of the first n terms of an AP is 5n - n 2 Sn = 5n − n 2 First term, a 1 = S 1 = 5 (1) − (1) 2 = 5 − 1 = 4 Sum of first two terms = S 2 = 5 (2) − (2) 2 = 10 − 4 = 6. …

The Sum of the First N Term Sofa an Ap is ` ( (3n^2) /2 + (5n) /2 ...

WebJan 8, 2024 · In an AP the sum of first n terms is 3n^2/2 + 5n/2 find the 25th term.In an AP the sum of first n terms is (3n^2+ 5n)/2 find the 25th term.In an AP the sum o... WebSum of ‘n’ terms of an A.P. 6 mins. Symmetric Representation of Three or More Terms in an A.P. 6 mins. Find a Value of Expression in AP using a Short Approach I. 4 mins. Find a … first presbyterian church odessa

The sum of the first n terms of an AP is (5n^2/2 +3n/2

WebThe sum of first n terms of an A.P is 5n−n 2. Find the n th term of this A.P A 6−5n B 6−2n C 5−2n D None of these Easy Solution Verified by Toppr Correct option is B) Given, S … WebIn an A.P the sum of first n terms is 3n2/2 + 13n/2. Find the 25th term arithmetic progression cbse class-10 1 Answer +1 vote answered Sep 30, 2024 by KajalAgarwal (45.2k points) selected Oct 1, 2024 by Vikash Kumar Best answer Given, Sn = 3n2/2 + 13n/2 ← Prev Question Next Question → Find MCQs & Mock Test JEE Main 2024 Test Series NEET Test … first presbyterian church ocean city nj

Arithmetic Progression-Definition, Nth Term, Formulas, Sum

in an A.P the sum of first n-terms is (5n^2)/2+3n/2 . Find the 17th ...

WebMar 23, 2024 · The sum of the third and the seventh terms of an AP is 6 and their product is 8. Find the sum of first sixteen terms of the AP. 3. A ladder has rungs 25 cm apart. (see Fig. 5.7). The rungs decrease uniformly in length from 45 cm at the bottom to 25 cm at the top. Web(11) Search the sum the first 20 terms of the numerical series in which 3 rl term is 7 also 7 in term is 2 more than three time its 3 rad term. Solution (12) Stylish an arithmetic series, which sum of first 11 conditions is 44 and one that of the next 11 terms is 55. first presbyterian church of ada oklahomaWebGiven, the expression for the sum of the series is Sₙ = 3n² + 5n. Last term, l is a k = 164. We have to find the value of k. Put n = 1, S₁ = 3(1)² + 5(1) = 3 + 5 = 8. ... If the sum of first 6 terms of an AP is 36 and that of the first 16 terms is 256, find the sum of th . . . . first presbyterian church ocala florida

"WebMar 22, 2024 · It is given that kth term = 5k + 1 ak = 5k + 1 To find sum of n terms, we use the formula Sn = n/2 [a + l] where Sn = sum of n terms of AP n = number of terms a = first term of A.P l = last term of A.P. " - In an ap the sum of first n terms is 5n 2/2

In an ap the sum of first n terms is 5n 2/2

In an AP, if Sₙ = 3n² + 5n and ak = 164, find the value of k - Cuemath

WebMar 30, 2024 · Given Sn = 2n2 + 3n Taking n = 1 S1 = 2 12 + 3 1 = 2 + 3 = 5 So, Sum of first term of AP is 5 But sum of first term will be the first term So, First term = a = 5 Taking n = 2 in Sn S1 = 2 22 + 3 2 S2 = 2 4 + 6 S2 = 8 + 6 S2 = 14 Sum of first 2 terms is 14 Finding 2nd term Sum of first 2 terms is 14 First term + Second term = 14 5 + a2 = 14 a2 = … WebApr 10, 2024 · Sum of first n terms of an AP S n = n 2 [ 2 a + ( n − 1) d] Where a =1st term & d =common difference Or, S n = n 2 [ a + a n] If there are only n terms in an AP, then a n =l, l=last term We will put n=1, 2 in the sum formula and evaluate the first and second term of the A.P. Then we can easily derive the common difference. By putting all these in

Did you know?

WebThe sum of first n terms of an A.P is given by S n=2n 2+3n. Find the sixteenth term of the A.P Easy Solution Verified by Toppr Sn= 2n(2a+(n−1)d) = 2n(2a−d)+n 22d=2n 2+3n ∴2= 2d⇒=4 and 22a−d=3 ∴2a=6+d=10 or, a=5. ∴a 16=a+(1+−1)d =5+15×4=65. Was this answer helpful? 0 0 Similar questions WebApr 16, 2024 · If the sum of first n terms is (3n2 + 5n), find its common difference. LIVE Course for free. ... If the sum of n terms of an A.P. is 3n^2 + 5n and its mth term is 164, find the value of m. ... In an AP, if Sn = 3n^2 + 5n and ak = 164, then find the value of k.

WebApr 20, 2024 · Apr 20, 2024 The sum of the first n term of an AP,denoted by Sn is given by Sn = n2 +8n So n th term of the series will be tn = Sn −Sn−1 = n2 + 8n − ((n −1)2 +8(n − 1)) ⇒ tn = 2n − 1 + 8 = 2n +7 Inserting n = 1,2,3.... we get For n = 1 → t1 = 2 ⋅ 1 +7 = 9 For n = 2 → t2 = 2 ⋅ 2 +7 = 11 For n = 3 → t3 = 2 ⋅ 3 +7 = 13 Hence first term t1 = 9 WebAnswer (1 of 3): If a is initial term & d is the common difference, then Sn = { 2a + ( n - 1 ) *d } * n/2 So S2n = { 2a + ( 2n - 1) *d } * n = 2an + 2n^2d - nd = (2a -d)n + 2n^2d = 3n + 14 n^2 Comparing coefficients with terms of n & n^2 we observe 2a - …

WebGeneral term of an AP is given by: a n = S n - S (n - 1) Calculation: Given: S n = 5n 2 + 6n and m th tem is 301. a n = S n - S (n - 1) After solving above equation we get . a n = 5(n) 2 + 6(n) - [5(n - 1) 2 + 6(n - 1)] a n = 5n 2 + 6n - 5n 2 - 5 + 10n - 6n + 6. a n = 10n + 1 . For 1st term, put n = 1. So, a 1 = 10 × 1 + 1 = 11. For 2nd term ... WebThe sum of the first n terms of an AP is (5n^2/2 + 3n/2). Find its nth term and the 20th term of this AP. asked Jul 9, 2024 in Arithmetic Progression by Anaswara (31.5k points) …

WebIf the nth term of an A.P. is 4n^2 - 5n, what is the sum of the first n term? Given that nth term of an A.P = Note that in any AP, nth term is always linear equation in and cannot be in second degree. However, the sum of first terms of an AP is a second degree equation in .

WebJun 4, 2014 · Question 1) Find the sum of the first 24 terms of the list of numbers whose nth term is given (3+2n). Question 2) For what value of n , are the nth terms of the two AP 63,65,67 and 3,10,17..... are equal ? Question 3) The pth term of an AP is a and qth term is b . Prove that the sum of its (p+q) terms = p+q/2{ a+ b+ (a-b/p-q)}. first presbyterian church oak ridgeWebAug 29, 2024 · If sum to n terms of an A.P. is 5n2 +6n and rth term is 401, then the value of r is Advertisement Expert-Verified Answer 19 people found it helpful Cosmique Answer: Value of r is 40 Explanation: Given, Sum of n terms of an AP is 5 n² + 6 n rth term of AP = aᵣ = 401 To find, Value of r So, Finding the AP first presbyterian church of aiken scWebThe sum of the first n terms of an AP is (5n 2 /2 +3n/2). Find its nth term and the 20th term of this AP. arithmetic progression class-10 1 Answer +2 votes answered Sep 14, 2024 by … first presbyterian church of alma miWebIn an AP the sum of first n terms is 3n2÷2+5n÷2 then find the 25th term. Solution Let the sum of n terms be given by Sn so Sn = 3n²/2+5n/2 S1 = 3(1)²/2+5(1)/2 = 3/2+5/2= 4 So 1st … first presbyterian church of ames iaWebThe sum of the first n terms of an AP in ( 5 n 2 2 + 3 n 2) .Find its nth term and the 20th term of this AP. Advertisement Remove all ads Solution s n = ( 5 n 2 2 + 3 n 2) = 1 2 ( 5 n 2 + 3 n) ..... (1) Replacing n by (n-1) in (i), we get: s n - 1 = 1 2 × [ 5 ( n - 1) 2 + 3 ( n - 1)] = 1 2 × [ 5 n 2 - 10 n + 5 + 3 n - 3] = 1 2 × [ 5 n 2 - 7 n + 2] first presbyterian church of altonWebLet S denotes the sum of first n terms of the AP. `∴ s_n = ( (3n^2) /2 +(5n) /2)` `⇒ s_(n-1) = (3(n-1)^2)/2 + (5 (n-1))/2` `= (3(n^2 - 2 n + 1 ))/2 + (5 (n-1))/2` `=(3n^2 - n-2)/2` ∴ n th term … first presbyterian church of annapolis mdWebJan 8, 2024 · In an AP the sum of first n terms is 3n^2/2 + 5n/2 find the 25th term.In an AP the sum of first n terms is (3n^2+ 5n)/2 find the 25th term.In an AP the sum o... first presbyterian church of ann arbor mi